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>> SPEAKER: Ejja timplimenta programm li
iqajjem l-utent għal integer

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iżda tkompli tħeġġeġ lilhom
għal numru sħiħ ieħor sakemm

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li numru sħiħ huwa pożittiv.

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Well, ejja tikteb dan, jinkludu cs50.h,
jinkludu standard io dot h, int

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[nulla] prinċipali.

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Issa ejja attwalment jibdew fil-pront il-
utent għal din integer filwaqt li jżommu

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f'moħħu li aħna rridu li reprompt
minnhom sa dak

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numru huwa attwalment pożittiv.

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>> So I taf tixtieq xi tip ta 'looping
tibni, iżda loop li tesegwixxi fi

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inqas darba.

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U mfakkra l loop do-waqt li tippermetti lill-
nagħmlu eżattament dan.

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Ejja kodiċi dan up.

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>> Ejja ewwel jiddikjara int - aħna ser
sejħa hija n - fejn jinħażnu l-

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integer utent.

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Ejja issa jagħmlu dan li ġej.

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Printf, jekk jogħġbok agħti lili int pożittiv.

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Ejja issa jiksbu li int użu
GetInt-librerija CS50 tal

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funzjoni, n gets GetInt.

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U issa aħna qed isir tagħmel xi ħaġa,
imma aħna qed tmur biex tixtieq li tagħmel dan

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filwaqt li n hija -

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liema? -

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inqas minn 1, jekk aħna tabilħaqq
jridu numru sħiħ pożittiv.

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>> Ejja jimxi 'l quddiem issa u jistampa.

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Jekk kollox huwa tajjeb, grazzi
għall-int pożittiv,

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virgola, ħlief il-fajl.

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Ejja issa jikkompilaw u run.

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>> Kun pożittiv dot slash pożittiv.

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U issa jien qed imqanqla
għal int pożittiv.

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Let me jikkoperaw ma 1.

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Grazzi għall-int pożittiv.

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>> Ejja issa terġa 'ssir dan il-programm
u mhux jikkoopera.

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Jekk jogħġbok agħti me int pożittiv.

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Kif dwar negattiv 1?

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Interessanti.

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Il-programm huwa diġà reprompted
me għal int.

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>> Ejja tkun ftit aktar
diffiċli b'0.

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Għadu mhux int pożittiv, hekk ejja
jikkooperaw u dan iż-żmien

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jipprovdu, għal darb'oħra, 1.

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Grazzi għall-int pożittiv.

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>> Issa huwa importanti li wieħed jinnota li I
iddikjarata n varjabbli tiegħi fuq il-linja 6,

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barra tal-linja do-waqt.

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Kieku I ddikjarat li n ġewwa tal tiegħi
do filwaqt li loop, speċifikament fuq, ngħidu aħna,

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linja 10, fejn I wkoll tikseb l-int minn
l-utent, li int n jkollha biss

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teżisti fi ħdan il-konfini tal-kaboċċi
braces li huma bħalissa fuq

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linja 8 u fuq il-linja 11.

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>> Fi kliem ieħor, n ikun scoped li
il-ġewwa ta 'dak loop do-waqt.

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Iżda l-problema hija li aħna wkoll
trid tuża n f'konformità 12

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ġewwa tal-kundizzjoni.

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Għalhekk anki jekk ma jidhrux daqshekk
pretty, huwa ferm intenzjonat li

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n huwa ddikjarat barra
dan loop do-waqt.

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