1 00:00:07,150 --> 00:00:08,850 [Powered by Google Translate] DAVID DICIURCIO: Hivyo dhana muhimu kufahamu katika 2 00:00:08,850 --> 00:00:11,010 programu hii ni dhana ya upeo. 3 00:00:11,010 --> 00:00:13,860 Wigo unaweza kuelezwa kama mazingira ambayo kutofautiana ni 4 00:00:13,860 --> 00:00:15,610 inayoonekana au kupatikana. 5 00:00:15,610 --> 00:00:18,150 Kwa mfano, hebu kusema sisi kuwa na kazi, kuu, kwamba ni 6 00:00:18,150 --> 00:00:22,570 zinatakiwa kuongezwa variable, x, kutoka moja mpaka mbili. 7 00:00:22,570 --> 00:00:25,690 Kama tunavyoona, kuu initializes x kwa moja, Prints 8 00:00:25,690 --> 00:00:28,740 nje Nakala baadhi, kisha anaendesha increment kazi, kabla ya 9 00:00:28,740 --> 00:00:30,540 uchapishaji zaidi maandishi. 10 00:00:30,540 --> 00:00:32,545 Kama kazi hii walikuwa kuendesha usahihi, ingekuwa 11 00:00:32,545 --> 00:00:34,120 magazeti nje x kama 2. 12 00:00:34,120 --> 00:00:35,370 Hebu jaribu hilo. 13 00:00:38,870 --> 00:00:43,075 >> Hivyo, kama unaweza kuona, kuu hafanyi kile sisi inatarajiwa. 14 00:00:43,075 --> 00:00:45,310 Ni anarudi thamani 1, badala 15 00:00:45,310 --> 00:00:47,150 kuliko 2 tulivyotarajia. 16 00:00:47,150 --> 00:00:50,060 Sababu ya mdudu hii inaweza kuelezwa na upeo. 17 00:00:50,060 --> 00:00:52,185 Katika kazi, kuu, sisi initialized x 18 00:00:52,185 --> 00:00:53,820 tu ndani ya kazi. 19 00:00:53,820 --> 00:00:56,580 Kwa maneno mengine, x variable ni alitangaza ndani ya nchi ndani 20 00:00:56,580 --> 00:00:58,640 kazi, kuu, na si kupatikana 21 00:00:58,640 --> 00:01:00,210 nje ya kazi. 22 00:01:00,210 --> 00:01:03,580 Tu kuu wanaweza kupata x katika hali hii. 23 00:01:03,580 --> 00:01:06,990 Wakati sisi kuwaita increment hatuwezi kupita x kama pembejeo, lakini 24 00:01:06,990 --> 00:01:08,960 tu nakala ya x. 25 00:01:08,960 --> 00:01:11,640 Kama matokeo ya hili, increment kazi tu anaongeza 26 00:01:11,640 --> 00:01:14,190 thamani 1 kwa nakala ya thamani ya x. 27 00:01:14,190 --> 00:01:16,170 Lakini si kwa X yenyewe. 28 00:01:16,170 --> 00:01:19,090 Wakati sisi kurudi kuu, x yenyewe hajabadilika wakati wote. 29 00:01:19,090 --> 00:01:22,370 Hivyo uchapishaji nje x tu mavuno thamani ya 1. 30 00:01:22,370 --> 00:01:24,890 >> Naam, basi, kwamba majani ya swali: jinsi lazima sisi kurekebisha 31 00:01:24,890 --> 00:01:26,230 kazi hii? 32 00:01:26,230 --> 00:01:29,500 Moja ufumbuzi ni kuwa na increment kurudi thamani. 33 00:01:29,500 --> 00:01:31,180 Kwa njia hii, increment kazi mapenzi 34 00:01:31,180 --> 00:01:33,350 kutupatia nyuma integer. 35 00:01:33,350 --> 00:01:35,420 Hivyo hapa ni code yetu upya kwa 36 00:01:35,420 --> 00:01:37,480 mbadala increment kazi. 37 00:01:37,480 --> 00:01:41,510 Hapa, sisi badala akarudi x + 1, badala ya mwisho tu 38 00:01:41,510 --> 00:01:44,070 na x kuwa sawa na x + 1. 39 00:01:44,070 --> 00:01:46,290 Pia, kuchukua taarifa kwamba sisi badala ya pato la 40 00:01:46,290 --> 00:01:49,630 increment, awali tupu, na int, na kusema kuwa 41 00:01:49,630 --> 00:01:52,230 increment sasa kupita nyuma thamani integer. 42 00:01:52,230 --> 00:01:55,000 Sasa, baada ya anaendesha increment, itakuwa kurejea kwa thamani ya 43 00:01:55,000 --> 00:01:56,535 2, hasa kama sisi lengo. 44 00:01:59,630 --> 00:02:02,260 >> Mwingine hali ambayo inaonyesha umuhimu wa upeo 45 00:02:02,260 --> 00:02:04,860 ni katika scopeloop.c. 46 00:02:04,860 --> 00:02:07,320 Katika kanuni hii, tuna kwa kitanzi ambayo variable 47 00:02:07,320 --> 00:02:10,310 jumla ni initialized wakati kila hatua. 48 00:02:10,310 --> 00:02:13,720 Kwa bahati mbaya, code hii haina kukusanya. 49 00:02:13,720 --> 00:02:16,690 Hii ni kwa sababu jumla variable kweli haipo 50 00:02:16,690 --> 00:02:18,550 nje kwa kitanzi. 51 00:02:18,550 --> 00:02:21,000 Vigezo alitangaza ndani ya matanzi tu lipo ndani ya 52 00:02:21,000 --> 00:02:23,967 kitanzi yenyewe na ni alionyesha katika makosa yetu 53 00:02:23,967 --> 00:02:25,880 ujumbe, jumla Undeclared. 54 00:02:25,880 --> 00:02:28,710 jumla ya variable bado kuwa alitangaza ndani ya wigo 55 00:02:28,710 --> 00:02:30,420 ya kazi kuu. 56 00:02:30,420 --> 00:02:33,610 Aidha, wakati kila iteration wa wetu kwa kitanzi, sisi 57 00:02:33,610 --> 00:02:36,340 ni reinitializing jumla wetu kwa 0. 58 00:02:36,340 --> 00:02:39,210 Hii yenyewe haina kuweka code kutoka kuandaa, lakini 59 00:02:39,210 --> 00:02:42,920 ingeweza kuzuia jumla kutoka milele summing kwa thamani 1 uliopita. 60 00:02:42,920 --> 00:02:45,760 >> Tena nini ni njia bora ya kutatua tatizo hili? 61 00:02:45,760 --> 00:02:48,520 Moja ya njia rahisi ni pamoja na kufanya jumla ya mitaa 62 00:02:48,520 --> 00:02:51,990 kazi, kuu, badala ya kitanzi yenyewe. 63 00:02:51,990 --> 00:02:55,210 Hii jumla ya kweli increment, na hatimaye, 64 00:02:55,210 --> 00:02:57,880 kuruhusu kuwa kuchapishwa baada ya kitanzi. 65 00:02:57,880 --> 00:03:00,093 Mbinu nyingine kwamba mimi itabidi tu kwa ufupi muhtasari ingekuwa 66 00:03:00,093 --> 00:03:02,190 kuwa matumizi ya vigezo kimataifa. 67 00:03:02,190 --> 00:03:04,890 Vigezo Global ni vigezo kwamba ni alitangaza kabla kuu 68 00:03:04,890 --> 00:03:07,860 kwamba kudumisha thamani zao katika mpango mzima. 69 00:03:07,860 --> 00:03:10,710 Bila shaka, kazi inaweza kubadilika thamani ya kimataifa, 70 00:03:10,710 --> 00:03:13,470 lakini hawana kwenda nje ya wigo kama vigezo mitaa. 71 00:03:13,470 --> 00:03:15,880 Hata hivyo, kwa kutumia vigezo kimataifa huelekea kipaji 72 00:03:15,880 --> 00:03:18,180 juu kama kubuni mbaya, kwa vile kuna njia bora ya 73 00:03:18,180 --> 00:03:20,080 kubadilishana data miongoni mwa kazi. 74 00:03:20,080 --> 00:03:21,920 Kwa mfano, kwa kutumia kuyatumia. 75 00:03:21,920 --> 00:03:24,250 Lakini zaidi juu ya kwamba wakati mwingine. 76 00:03:24,250 --> 00:03:26,670 >> Hatimaye, ni muhimu kuwa na ufahamu wa upeo 77 00:03:26,670 --> 00:03:29,550 katika muktadha wa kumbukumbu ya kompyuta, au RAM. 78 00:03:29,550 --> 00:03:32,470 Wakati sisi nitafanya mpango, mitaa vigezo na majukumu 79 00:03:32,470 --> 00:03:34,040 ni aliongeza kwa mahali maalum katika 80 00:03:34,040 --> 00:03:36,010 RAM aitwaye stack. 81 00:03:36,010 --> 00:03:39,230 Kama kurudi kazi, muafaka stack ya vigezo ni 82 00:03:39,230 --> 00:03:43,910 ufanisi kuondolewa kutoka stack kumkomboa up kumbukumbu zaidi. 83 00:03:43,910 --> 00:03:46,750 Hivyo wakati marekebisho upeo, hakikisha unakumbuka hizi tatu 84 00:03:46,750 --> 00:03:47,980 muhimu pointi. 85 00:03:47,980 --> 00:03:51,220 Moja, upeo inaweza kuwa ama ndani au wa kimataifa. 86 00:03:51,220 --> 00:03:53,990 Ni inategemea ambapo variable ni alitangaza. 87 00:03:53,990 --> 00:03:57,040 Mbili, vigezo alitangaza au initialized katika kazi ni 88 00:03:57,040 --> 00:03:59,510 mitaa kwa kazi hiyo na haiwezi kubadilishwa kwa wengine 89 00:03:59,510 --> 00:04:02,790 kazi, angalau si bila kutumia kuyatumia. 90 00:04:02,790 --> 00:04:05,340 Hatimaye, vigezo ni pia mitaa matanzi kwamba ni 91 00:04:05,340 --> 00:04:06,490 alitangaza ndani. 92 00:04:06,490 --> 00:04:08,100 vigezo si kupatikana 93 00:04:08,100 --> 00:04:09,860 nje ya kitanzi. 94 00:04:09,860 --> 00:04:11,170 >> Hayo ni yote kwa sasa juu ya upeo. 95 00:04:11,170 --> 00:04:12,420 Shukrani kwa ajili ya kuangalia.