1 00:00:00,000 --> 00:00:00,330 2 00:00:00,330 --> 00:00:02,700 >> SPEAKER 1: Ejja ngħidu I tixtieq li tikteb programm li tistampa float, 3 00:00:02,700 --> 00:00:05,700 speċifikament ir-riżultat ta 'diviżjoni 1 minn 10. 4 00:00:05,700 --> 00:00:08,830 Ukoll, l-ewwel instincts tiegħi ikun li tikteb dan il-programm kif ġej. 5 00:00:08,830 --> 00:00:18,160 Float f daqs 1 maqsum f'10, u mbagħad print f tal mija .1 f, biex b'hekk 6 00:00:18,160 --> 00:00:22,270 jfisser li nixtieq li jistampaw float sa post deċimali wieħed, 7 00:00:22,270 --> 00:00:26,490 backslash n comma f. 8 00:00:26,490 --> 00:00:28,270 Ejja issa jiġbor dan il-programm. 9 00:00:28,270 --> 00:00:32,980 Jagħmlu float 0 dot slash float 0. 10 00:00:32,980 --> 00:00:34,140 >> Ukoll, li mhux tajba ħafna. 11 00:00:34,140 --> 00:00:40,210 Jien pjuttost ċert li 1 maqsum f'10, jew 1/10 mhuwiex 0.0, iżda 0.1, u għadhom 12 00:00:40,210 --> 00:00:42,820 hawn jien jaraw fuq l-iskrin 0.0. 13 00:00:42,820 --> 00:00:43,860 X'qed jiġri? 14 00:00:43,860 --> 00:00:47,790 Ukoll, jirriżulta li fil-c, jekk inti jaqsam xi int minn int, 15 00:00:47,790 --> 00:00:49,090 ikollok lura int. 16 00:00:49,090 --> 00:00:54,810 U hekk anke jekk 1 maqsum f'10 hija tabilħaqq 0.10, 0.1 ma jistgħux jitwaħħlu b'mod int, 17 00:00:54,810 --> 00:00:58,930 u għalhekk liema c ma huwa taqta ', jew throws bogħod kollox wara l- 18 00:00:58,930 --> 00:01:01,770 post deċimali, u b'hekk tħalli us mal biss 0. 19 00:01:01,770 --> 00:01:04,989 >> Imma allura, ovvjament, li jistampa f, aħna jispeċifikaw li aħna tixtieq li jistampaw f biex 20 00:01:04,989 --> 00:01:09,260 post deċimali wieħed, u sabiex 0 hija murija bħala 0.0. 21 00:01:09,260 --> 00:01:11,540 Well, b'mod ċar din hija problema li teħtieġ soluzzjoni. 22 00:01:11,540 --> 00:01:14,025