1 00:00:00,000 --> 00:00:00,330 2 00:00:00,330 --> 00:00:01,830 >> DAVID MALAN: Bel蓹 ki, nec蓹 Biz bu problemi h蓹ll? 3 00:00:01,830 --> 00:00:05,310 Yax艧谋, asan yolu yaln谋z qar艧谋s谋n谋 almaq 眉莽眉n ints c蓹mi, v蓹 蓹v蓹zin蓹 m眉蓹yy蓹n 4 00:00:05,310 --> 00:00:06,960 bir float bir float. 5 00:00:06,960 --> 00:00:12,460 X眉susil蓹, nin 1.0 1 d蓹yi艧dirm蓹k imkan v蓹 10.0 10, v蓹 sonra bu saxlamaq 6 00:00:12,460 --> 00:00:14,380 floats1.c kimi fayl. 7 00:00:14,380 --> 00:00:20,270 Indi etm蓹k floats1 il蓹 t蓹rtib ed蓹k, v蓹 sonra floats1 il蓹 ax谋r. 8 00:00:20,270 --> 00:00:22,590 V蓹 indi m蓹n h蓹qiq蓹t蓹n 0.1 g枚r眉r眉k. 9 00:00:22,590 --> 00:00:25,540 >> Biz h蓹ll ed蓹 bil蓹r ba艧qa bir yolu var Bu ki, t枚km蓹 istifad蓹 edir. 10 00:00:25,540 --> 00:00:29,750 T枚km蓹 bir konvertasiya prosesi data type ba艧qa, bu f蓹rz 11 00:00:29,750 --> 00:00:31,130 bunu 蓹h蓹miyy蓹t k蓹sb edir. 12 00:00:31,130 --> 00:00:34,370 Bu halda, m蓹n n蓹 ed蓹 bil蓹r geri getm蓹k edir M蓹n kod versiyas谋 13 00:00:34,370 --> 00:00:40,050 int 10 int bir ay谋r谋c谋, lakin M蓹n a艧kar compiler dey蓹 bil蓹r 14 00:00:40,050 --> 00:00:43,990 M蓹n bunu sanki 1 m眉alic蓹 etm蓹k ist蓹yir蓹m ki, bir bir int var, baxmayaraq ki, 眉zm蓹k v蓹 15 00:00:43,990 --> 00:00:48,270 M蓹n bir float kimi 10 m眉alic蓹 etm蓹k ist蓹rdim, Bu, 莽ox, bir int olsa. 16 00:00:48,270 --> 00:00:51,760 >> 茝slind蓹, m蓹n yaln谋z 眉z 蓹ld蓹 ed蓹 bil蓹r , bir float 眉莽眉n bu bir t枚km蓹 17 00:00:51,760 --> 00:00:55,350 莽眉nki bir bir float b枚lm蓹k 蓹g蓹r int v蓹 ya float t蓹r蓹find蓹n int, C ed蓹c蓹k 18 00:00:55,350 --> 00:00:57,550 siz蓹 bir 眉z蓹n point d蓹y蓹r qay谋tmaq. 19 00:00:57,550 --> 00:01:01,150 Lakin bu halda, yax艧谋 t蓹dbir 眉莽眉n, I will compile, 眉z眉b gedirdi 莽evir蓹 20 00:01:01,150 --> 00:01:06,380 etm蓹k floats1 il蓹 m蓹nim proqram, sonra dot 莽izgi floats1 il蓹 run, 21 00:01:06,380 --> 00:01:08,770 v蓹 m蓹n d蓹 0.1 g枚r眉r眉k. 22 00:01:08,770 --> 00:01:10,983