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>> HOPARL脰R: bir proqram h蓹yata ed蓹k ki,
bir tam 眉莽眉n istifad蓹莽i ister

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lakin onlar谋n isteyen davam edir
ba艧qa tam q蓹d蓹r 眉莽眉n

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ki, tam m眉sb蓹tdir.

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Yax艧谋, cs50.h daxildir, bu yazmaq imkan,
standart io dot h, int daxildir

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蓹sas [void].

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陌ndi h蓹qiq蓹t蓹n t蓹klif ba艧lamaq bildirin
Bu tam 眉莽眉n istifad蓹莽i tutarken

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biz reprompt etm蓹k ist蓹yir蓹m ki, a臒la
onlara q蓹d蓹r

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say谋 蓹slind蓹 m眉sb蓹tdir.

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>> M蓹n loop bir n枚v laz谋md谋r
tikintisi, lakin h蓹yata ki, bir loop

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蓹n az谋 bir d蓹f蓹.

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V蓹 do-is蓹 loop imkan verir geri
biz蓹 m蓹hz bunu.

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Bu q蓹d蓹r kod ed蓹k.

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>> Ilk bir int b蓹yan ed蓹k - biz will
n z蓹ng - hans谋 saxlamaq 眉莽眉n

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陌stifad蓹莽il蓹rin tam.

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陌ndi a艧a臒谋dak谋 ed蓹k.

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Printf, m蓹n蓹 bir m眉sb蓹t int verin.

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陌ndi almaq ed蓹k ki, istifad蓹 int
CS50 kitabxana GetInt

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funksiyas谋, n GetInt olur.

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陌ndi biz bir 艧ey bunu tamamlay谋n,
lakin biz bunu ist蓹yir蓹m olacaq

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n is蓹 -

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n蓹? -

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1-d蓹n az, h蓹qiq蓹t蓹n biz 蓹g蓹r
bir m眉sb蓹t tam ist蓹yirik.

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>> Indi ir蓹li getm蓹k v蓹 莽ap ed蓹k.

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B眉t眉n yax艧谋, thanks varsa
m眉sb蓹t int,

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n枚qt蓹li verg眉l, fayl saxlamaq.

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陌ndi t蓹rtib v蓹 run ed蓹k.

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>> M眉sb蓹t dot 莽izgi m眉sb蓹t olun.

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V蓹 indi istenir al谋ram
m眉sb蓹t int.

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M蓹n蓹 1 il蓹 蓹m蓹kda艧l谋q ed蓹k.

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M眉sb蓹t int 眉莽眉n t蓹艧蓹kk眉r edirik.

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>> Indi bu proqram t蓹krar ed蓹k
v蓹 蓹m蓹kda艧l谋q.

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M蓹n蓹 bir m眉sb蓹t int verin.

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Nec蓹 m蓹nfi 1 haqq谋nda?

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Maraql谋.

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Proqram art谋q reprompted olunur
int 眉莽眉n m蓹n蓹.

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>> Nin bir az daha olaq
0 il蓹 莽蓹tin.

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H蓹l蓹 bir m眉sb蓹t int, bel蓹 ed蓹k
bu d蓹f蓹 蓹m蓹kda艧l谋q v蓹

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, yen蓹 1 t蓹min edir.

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M眉sb蓹t int 眉莽眉n t蓹艧蓹kk眉r edirik.

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>> 陌ndi ki, m蓹n qeyd etm蓹k vacibdir
x蓹tt 6 m蓹nim d蓹yi艧蓹n n elan,

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do-is蓹 loop k蓹narda.

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M蓹n 蓹v蓹zin蓹 daxilind蓹 n elan etdi m蓹nim
do-is蓹 loop, x眉susi, dem蓹k,

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M蓹n d蓹 int almaq line 10,
istifad蓹莽i ki, int n olard谋 yaln谋z

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Bu buruq s蓹rh蓹dl蓹ri daxilind蓹 m枚vcud
Hal-haz谋rda olan a艧谋rma

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line 8 v蓹 line 11.

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>> Ba艧qa s枚zl蓹, n scoped olunacaq
ki, do-is蓹 loop daxilind蓹.

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Amma problem ki, biz d蓹
line 12 n istifad蓹 etm蓹k ist蓹diyiniz

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Bu 艧蓹rt daxilind蓹.

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Bel蓹 g枚r眉nm眉r Bel蓹 ki, baxmayaraq
olduqca, bu 莽ox q蓹sd蓹n var

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n xaricind蓹 elan
bu do-is蓹 loop.

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