1
00:00:00,000 --> 00:00:00,340

2
00:00:00,340 --> 00:00:01,960
>> SPEAKER 1: Ejja issa jiffissaw
dak il-programm li għadda.

3
00:00:01,960 --> 00:00:04,920
U din id-darba, ejja talloka b'mod espliċitu
xi memorja li fiha l-

4
00:00:04,920 --> 00:00:06,550
input utent se jiġu maħżuna.

5
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Biex tagħmel dan, ejja Hone fl fuq l-ewwel
linja tal-kodiċi fejn aħna iddikjarata s

6
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qabel li tkun stilla char.

7
00:00:11,590 --> 00:00:14,210
Din id-darba, ejja 'jiddikjara mill-ġdid
huwa kif ġej -

8
00:00:14,210 --> 00:00:19,380
bracket 16 char i, per eżempju,
parentesi magħluqa.

9
00:00:19,380 --> 00:00:23,690
>> Fi kliem ieħor, ejja tiddikjara s li xejn
itwal għandu jkun indirizz ta 'karattru,

10
00:00:23,690 --> 00:00:26,610
iżda pjuttost firxa ta '16 karattri.

11
00:00:26,610 --> 00:00:30,295
Dan il-mod, l-utent tista 'tip sa 15
karattri u xorta jħallu lok għal

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00:00:30,295 --> 00:00:31,570
a terminatur null.

13
00:00:31,570 --> 00:00:35,870
Ejja tipproċedi biex Save, jikkumpilaw,
u Mexxi dan il-programm.

14
00:00:35,870 --> 00:00:40,770
Kun scanf2 scanf2 dot slash.

15
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Ejja issa tip string simili hello,
u aħna qed irringrazzja għall-bonjour.

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>> Issa, hemm għadu problema.

17
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I biss ittajpjat fil hello, li huwa biss
ħames karattri, flimkien 1 għall-null

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00:00:50,140 --> 00:00:50,445
terminatur.

19
00:00:50,445 --> 00:00:53,610
Hija Jifdal biss
ħtieġa għal sitt bytes.

20
00:00:53,610 --> 00:00:56,740
>> Iżda sfortunatament, aħna biss
allokat 16 b'kollox.

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Mela jekk l-utent fil-fatt tipi fil-16
karattri, jew 17, jew diversi mijiet

22
00:01:01,305 --> 00:01:04,410
karattri, aħna qed għadhom mhux se
jkollhom biżżejjed spazju fil-memorja għall-

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input utent.

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00:01:05,400 --> 00:01:07,750
U fil-fatt, dan huwa dak li jagħmel
jkollna input utent hekk

25
00:01:07,750 --> 00:01:08,940
diffiċli b'mod ġenerali.

26
00:01:08,940 --> 00:01:12,270
U fil-fatt, dan huwa għaliex aħna implimentati
il-funzjoni string get fl-ewwel

27
00:01:12,270 --> 00:01:13,900
post fil-librerija CS50 -

28
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figura kif jimmaniġġjaw dawk
sitwazzjonijiet fejn it-tipi utent fil

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karattri aktar minn we
antiċipat fil-bidu.

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00:01:19,710 --> 00:01:21,750
>> Franchement, mingħajr kompletament
kitba mill-ġdid dan il-programm,

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00:01:21,750 --> 00:01:23,290
hemm l-ebda soluzzjoni nadif.

32
00:01:23,290 --> 00:01:26,970
Pjuttost, dak li nixtiequ għandek tagħmel hu li tikseb
karattru mill-utent wieħed kull

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00:01:26,970 --> 00:01:28,860
time, u għal darb'oħra.

34
00:01:28,860 --> 00:01:32,510
U f'kull punt jekk aħna realizzata aħna qed
tal-memorja, rridu naraw li fil-

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00:01:32,510 --> 00:01:36,450
dak il-punt jmorru lura u jerġgħu jallokaw
xi memorja aktar, kopja tal-l-utent

36
00:01:36,450 --> 00:01:39,400
input preċedenti mill-ewwel chunk tagħna
tal-memorja fil-ġdida,

37
00:01:39,400 --> 00:01:40,810
blokki akbar ta 'memorja.

38
00:01:40,810 --> 00:01:44,610
U mbagħad irrepeti l-proċess mill-ġdid u
mill-ġdid sakemm l-utent isir provvediment

39
00:01:44,610 --> 00:01:45,860
input tiegħu jew tagħha.

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00:01:45,860 --> 00:01:48,246