1 00:00:00,000 --> 00:00:00,500 2 00:00:00,500 --> 00:00:01,960 SPIKA 1: Hebu majadiliano juu ya maji. 3 00:00:01,960 --> 00:00:07,280 Katika tatizo hili, tunaomba user kuwaambia sisi kwa muda gani katika dakika ya kuoga yao ilikuwa 4 00:00:07,280 --> 00:00:11,040 na kisha sisi hesabu sawa idadi ya chupa za maji 5 00:00:11,040 --> 00:00:12,970 kwamba kuoga yao kutumika. 6 00:00:12,970 --> 00:00:16,379 >> Kwa hiyo kile ni yetu kwa-do kwa tatizo hili? 7 00:00:16,379 --> 00:00:20,050 Kwanza, sisi ni kwenda kutaka kuchochea na kisha kuhalalisha 8 00:00:20,050 --> 00:00:22,100 pembejeo kwamba mtumiaji inatupa. 9 00:00:22,100 --> 00:00:24,790 Mara sisi kuhakikisha kwamba sisi na user pembejeo halali, 10 00:00:24,790 --> 00:00:28,230 tunakwenda mahesabu sawa idadi ya chupa za maji 11 00:00:28,230 --> 00:00:30,770 kwamba mtumiaji alikuwa wakati wa kuoga yao, na kisha tuko 12 00:00:30,770 --> 00:00:33,720 kwenda kuwaambia yao kwa uchapishaji nje idadi hiyo. 13 00:00:33,720 --> 00:00:37,230 >> Basi hebu kukabiliana na kwanza wetu Kazi, na hivyo kusababisha na kuthibitisha 14 00:00:37,230 --> 00:00:38,550 user pembejeo. 15 00:00:38,550 --> 00:00:40,910 Kwa hili tumekuwa imeandikwa kazi kwa ajili ya wewe kuitwa 16 00:00:40,910 --> 00:00:43,950 get_int iko katika CS50 maktaba. 17 00:00:43,950 --> 00:00:48,710 get_int kuhakikisha kwamba pembejeo user integer, hivyo idadi yoyote chanya, 18 00:00:48,710 --> 00:00:51,700 idadi hasi, au zero zote ni kukubalika. 19 00:00:51,700 --> 00:00:55,900 Lakini kama mtumiaji pembejeo kitu kingine chochote, hivyo macho yoyote ya barua au namba 20 00:00:55,900 --> 00:00:59,710 au namba decimal, basi user utakuwa ilisababisha jaribu tena 21 00:00:59,710 --> 00:01:04,319 na kazi hawatakubali kitu chochote mpaka user inawapa integer. 22 00:01:04,319 --> 00:01:06,410 >> Hivyo ni jinsi gani sisi kutumia get_int? 23 00:01:06,410 --> 00:01:10,830 Kama wewe kufungua workspace yako na kuunda faili aitwaye integer.c hebu 24 00:01:10,830 --> 00:01:12,110 aina zifuatazo. 25 00:01:12,110 --> 00:01:14,760 Hashtag ni pamoja na cs50.h. 26 00:01:14,760 --> 00:01:18,480 Hii ni muhimu kwa sababu get_int ni cs50 maktaba kazi, 27 00:01:18,480 --> 00:01:21,890 hivyo ni lazima hashtag ni pamoja na tamko lake ili 28 00:01:21,890 --> 00:01:23,370 kutumia kazi. 29 00:01:23,370 --> 00:01:26,570 Na kisha katika kuu yangu kazi mimi nina kwenda tu 30 00:01:26,570 --> 00:01:29,560 tu piga kazi get_int. 31 00:01:29,560 --> 00:01:31,750 >> Basi hebu kukimbia hii na kuona jinsi kazi. 32 00:01:31,750 --> 00:01:35,092 Nimekuwa tayari ulioandaliwa hayo, hivyo hebu tu kwenda mbele na kuendesha mpango huu, 33 00:01:35,092 --> 00:01:36,480 ./integer. 34 00:01:36,480 --> 00:01:39,880 Hapa nina haraka na hapa ndipo mimi pembejeo thamani. 35 00:01:39,880 --> 00:01:44,880 Sema mimi kuweka katika baadhi tu ya integer, 50, anamwepusha mpango na quits 36 00:01:44,880 --> 00:01:45,960 na hiyo ni kwamba. 37 00:01:45,960 --> 00:01:49,350 >> Lakini kusema mimi kukimbia tena na Mimi pembejeo kitu kingine. 38 00:01:49,350 --> 00:01:51,350 Labda, hello dunia. 39 00:01:51,350 --> 00:01:55,660 Hiyo si integer hivyo mpango zitasababisha me kujaribu tena. 40 00:01:55,660 --> 00:01:59,160 Hebu jaribu tena na labda decimal wakati huu. 41 00:01:59,160 --> 00:02:03,450 0.5, tena, si integer hivyo Mpango hawatakubali ni 42 00:02:03,450 --> 00:02:05,290 na kutakuwa na kuniambia kujaribu tena. 43 00:02:05,290 --> 00:02:07,070 Basi hebu kuwapa idadi nyingine. 44 00:02:07,070 --> 00:02:09,830 mpango anapokea yake, quits, na sisi ni kosa. 45 00:02:09,830 --> 00:02:13,520 >> Hivyo basi, tuna kazi ambayo inaruhusu sisi na kuhakikisha 46 00:02:13,520 --> 00:02:16,790 kwamba mtumiaji pembejeo integer, lakini jinsi gani tunaweza 47 00:02:16,790 --> 00:02:20,330 kweli kuweka wimbo wa integer inputted na mtumiaji? 48 00:02:20,330 --> 00:02:25,260 Naam, kila tutaweza kufanya ni duka thamani hii katika kutofautiana, kusema n. 49 00:02:25,260 --> 00:02:30,580 Hivyo kama mimi kutangaza integer n, na mimi kuweka kwamba thamani ya get_int, 50 00:02:30,580 --> 00:02:34,700 kisha n kisha kuhifadhi chochote kuthamini user inputted. 51 00:02:34,700 --> 00:02:38,620 >> Haki ya wote, hivyo sasa tumekuwa kuhakikisha kwamba user itatupa integer 52 00:02:38,620 --> 00:02:42,550 na tunajua jinsi ya kuweka wimbo ya integer, lakini kumbuka, 53 00:02:42,550 --> 00:02:45,610 integers ni wote chanya na hasi. 54 00:02:45,610 --> 00:02:49,110 Hivyo ni kweli haina mantiki katika mazingira ya tatizo hili 55 00:02:49,110 --> 00:02:53,570 kwamba mtumiaji inachukua kuoga ya kusema dakika hasi 12. 56 00:02:53,570 --> 00:02:59,310 Kwa hiyo, tunahitaji kuhakikisha kwamba mtumiaji kweli inatupa sifuri. 57 00:02:59,310 --> 00:03:02,130 Sasa hatuna tu kazi moja kwa kuwa, 58 00:03:02,130 --> 00:03:04,620 hivyo tunakwenda kuwa na kujenga kwamba sisi wenyewe. 59 00:03:04,620 --> 00:03:07,190 >> Hivyo tunataka daima kuchochea mtumiaji 60 00:03:07,190 --> 00:03:09,730 mpaka wao kutupatia sifuri. 61 00:03:09,730 --> 00:03:14,300 Kama mimi nina kufanya kitu kuendelea basi hiyo ni sawa na kitanzi, marudio. 62 00:03:14,300 --> 00:03:19,130 Hivyo moja ya constructs kwamba sisi kutumia katika c kutekeleza marudio na loops 63 00:03:19,130 --> 00:03:20,410 ni kitanzi wakati. 64 00:03:20,410 --> 00:03:23,020 Hivyo kitanzi wakati, kama inavyoonekana hapa, nitafanya 65 00:03:23,020 --> 00:03:27,030 vilivyomo katika mwili wa kitanzi kama muda mrefu kama kutokana na hali kutathmini 66 00:03:27,030 --> 00:03:27,900 kwa kweli. 67 00:03:27,900 --> 00:03:30,640 Haraka kama hali hiyo kutathmini kwa uongo, basi 68 00:03:30,640 --> 00:03:34,830 mpango wa kuendelea na chochote inakuja baada ya mwili wa kitanzi. 69 00:03:34,830 --> 00:03:39,400 >> Hivyo wakati loops ni kwenda kuwa muhimu kweli kweli katika CS50. 70 00:03:39,400 --> 00:03:42,590 Lakini katika hili hasa kesi, tunajua kwamba tuko 71 00:03:42,590 --> 00:03:48,140 kwenda kuchochea mtumiaji angalau mara moja na kisha tu kitanzi kama ni lazima. 72 00:03:48,140 --> 00:03:51,080 Hivyo hapa sisi kuja maalum kujenga na hiyo ni 73 00:03:51,080 --> 00:03:55,020 sawa na wakati kitanzi aitwaye kitanzi do-wakati. 74 00:03:55,020 --> 00:03:58,840 >> Hivyo kitanzi do-wakati executes mwili wa kitanzi angalau mara moja 75 00:03:58,840 --> 00:04:01,750 na kisha ni hundi ya kuona kama ni lazima kutekeleza, 76 00:04:01,750 --> 00:04:05,310 kinyume na kitanzi wakati, ambayo itakuwa kuangalia hali 77 00:04:05,310 --> 00:04:07,200 na kisha kutekeleza mwili. 78 00:04:07,200 --> 00:04:11,880 Hivyo katika kitanzi do-wakati gani tupate kufanya ni kuchochea mtumiaji kwa integer, 79 00:04:11,880 --> 00:04:14,450 na kisha kuangalia kama ni batili au la. 80 00:04:14,450 --> 00:04:18,130 Kama ni batili, basi tutaweza kurudia utaratibu kuuliza mtumiaji 81 00:04:18,130 --> 00:04:22,290 kutupa integer mwingine, na kisha tu wakati kwamba integer ni halali, 82 00:04:22,290 --> 00:04:25,060 tutaweza kuendelea chochote huja baadaye. 83 00:04:25,060 --> 00:04:28,030 >> Sasa utasikia taarifa kwamba tamko la integer n 84 00:04:28,030 --> 00:04:31,670 ni tofauti kidogo kwa nini sisi alifanya kabla katika mfano uliopita 85 00:04:31,670 --> 00:04:33,640 na hii ni kwa sababu ya upeo. 86 00:04:33,640 --> 00:04:37,920 Kama sisi alikuwa ametangaza integer n ndani ya mwili wa kitanzi do-wakati, 87 00:04:37,920 --> 00:04:42,640 kisha sisi bila kuwa na uwezo wa kupata kwamba thamani ya n nje ya wale curly 88 00:04:42,640 --> 00:04:45,050 inakabiliwa na kuonyesha mwili wa kitanzi. 89 00:04:45,050 --> 00:04:51,080 Lakini hatuwezi kwa kweli wanataka kupata thamani ya n baadaye katika mpango wetu. 90 00:04:51,080 --> 00:04:55,730 >> OK, hivyo sasa hebu majadiliano juu ya nini hali hii inapaswa kuwa. 91 00:04:55,730 --> 00:05:00,400 Tunataka tu reprompt user kwa muda mrefu kama n ni batili. 92 00:05:00,400 --> 00:05:04,640 Hivyo kufikiri kwa mwenyewe nini ni batili integer thamani bila kuangalia kama 93 00:05:04,640 --> 00:05:08,060 na kisha kuunda Boolean kujieleza kueleza kwamba. 94 00:05:08,060 --> 00:05:13,070 >> Sisi ni karibu kumaliza subtask yetu ya kusababisha na kuthibitisha user pembejeo. 95 00:05:13,070 --> 00:05:16,010 Basi hebu kufanya hili kidogo bit user zaidi ya kirafiki 96 00:05:16,010 --> 00:05:18,390 na kutoa user kidogo bit habari zaidi 97 00:05:18,390 --> 00:05:20,510 ya nini sisi ni kusababisha yao kwa. 98 00:05:20,510 --> 00:05:24,500 Basi hebu kuchochea mtumiaji, per spec, na dakika kamba. 99 00:05:24,500 --> 00:05:28,935 Hivyo kwa kutumia kauli yako printf, kufanya uhakika kwamba mechi hii hasa. 100 00:05:28,935 --> 00:05:30,230 >> Sawa. 101 00:05:30,230 --> 00:05:33,840 Hivyo basi, tuna user halali pembejeo, integer chanya 102 00:05:33,840 --> 00:05:37,400 thamani kwa muda wa dakika ngapi walitumia katika oga. 103 00:05:37,400 --> 00:05:41,300 Hivyo nini ijayo ni mahesabu ya sawa idadi ya chupa. 104 00:05:41,300 --> 00:05:45,250 Nini tunakwenda kufanya hapa inaweza kuwa wazi sana kwa mara ya kwanza, 105 00:05:45,250 --> 00:05:46,640 na kwamba ni sawa. 106 00:05:46,640 --> 00:05:49,320 Nini tunataka kufanya ni sisi wanataka kuanza kufanya mazoezi 107 00:05:49,320 --> 00:05:53,810 wazo la kuchunguza mwelekeo na kuendeleza kanuni kwa ajili ya tatizo. 108 00:05:53,810 --> 00:05:57,200 >> Hivyo sisi ni aliiambia kwa spec kwamba dakika moja katika oga 109 00:05:57,200 --> 00:05:59,960 ni sawa na chupa 12 za maji. 110 00:05:59,960 --> 00:06:03,020 Hivyo basi dakika mbili ingekuwa kuwa sawa na 24, 111 00:06:03,020 --> 00:06:05,850 na dakika tano ingekuwa kuwa sawa na 60. 112 00:06:05,850 --> 00:06:08,390 Hivyo sasa kama unadhani nimepata ni, basi hebu 113 00:06:08,390 --> 00:06:10,390 kuona kama unaweza kuja na muundo au formula 114 00:06:10,390 --> 00:06:14,990 kueleza kama sisi kusema, n dakika, jinsi wengi chupa za maji 115 00:06:14,990 --> 00:06:17,930 ingekuwa kwamba kuwa walionyesha katika suala la n? 116 00:06:17,930 --> 00:06:20,680 >> Tena, hata kama hii inaweza kuwa rahisi mara ya kwanza, 117 00:06:20,680 --> 00:06:23,240 baadaye wakati sisi kupata matatizo ngumu zaidi 118 00:06:23,240 --> 00:06:26,360 tunakwenda wanataka kupata katika mazoezi ya kutambua 119 00:06:26,360 --> 00:06:30,120 chati na kuendeleza kanuni kufikiri mambo haya nje. 120 00:06:30,120 --> 00:06:33,450 >> Katika c una upatikanaji wa kiwango cha hesabu shughuli, 121 00:06:33,450 --> 00:06:36,520 Aidha, kutoa, kuzidisha, na mgawanyiko. 122 00:06:36,520 --> 00:06:38,420 Hivyo mimi itabidi kuondoka kwa wewe sasa kufikiri 123 00:06:38,420 --> 00:06:41,300 jinsi ya kueleza sawa idadi ya chupa 124 00:06:41,300 --> 00:06:43,990 kwamba mtumiaji zinazotumiwa wakati wa kuoga yao. 125 00:06:43,990 --> 00:06:45,700 >> Yote ya haki, sisi ni karibu kufanyika. 126 00:06:45,700 --> 00:06:50,650 Tumekuwa ilisababisha user kwa mchango wao, tumekuwa kuhakikisha kwamba ni halali pembejeo, 127 00:06:50,650 --> 00:06:53,330 na kisha tumekuwa figured nje ya jinsi kwa mahesabu sawa 128 00:06:53,330 --> 00:06:55,480 idadi ya chupa kwamba wao zinazotumiwa. 129 00:06:55,480 --> 00:06:59,430 Hivyo jambo la mwisho kufanya ni pato sawa idadi ya chupa 130 00:06:59,430 --> 00:07:02,410 na hopefully kuhamasisha yao ya kuhifadhi maji. 131 00:07:02,410 --> 00:07:06,270 >> Outputting thamani itakuwa kuwa printf taarifa yake. 132 00:07:06,270 --> 00:07:09,720 Kama nilitaka kukuambia kuwa mimi kuwa kipenzi tatu, kwa mfano, 133 00:07:09,720 --> 00:07:13,090 Mimi wanaweza kutumia kauli printf kwamba inaonekana kitu kama hiki. 134 00:07:13,090 --> 00:07:15,880 Nina kipenzi tatu, na mpya line kwa nzuri formatting. 135 00:07:15,880 --> 00:07:17,880 >> Sasa sisi hawataki tu kwa bidii kificho mambo. 136 00:07:17,880 --> 00:07:20,740 Kusema idadi ya yangu kipenzi mabadiliko baada ya muda. 137 00:07:20,740 --> 00:07:25,080 Basi mimi nina kwenda kufanya matumizi ya placeholders katika printf kauli yangu. 138 00:07:25,080 --> 00:07:27,350 Hivyo hapa namba yangu ni integer. 139 00:07:27,350 --> 00:07:31,480 Hivyo nina kwenda kufanya placeholder kwa integer kutumia% i. 140 00:07:31,480 --> 00:07:33,930 Mimi nina kwenda kuandika kamba, na kisha baada ya kamba 141 00:07:33,930 --> 00:07:38,000 Mimi kuandika comma na kisha kutofautiana kwamba nataka magazeti. 142 00:07:38,000 --> 00:07:42,730 Hivyo kwamba thamani itakuwa kuchapishwa badala ya kuwa placeholder,% i. 143 00:07:42,730 --> 00:07:47,630 >> Unaweza kutumia placeholders, kama vizuri, kwa ikifungwa na% f. 144 00:07:47,630 --> 00:07:50,420 Unaweza pia kuwa na nyingi placeholders katika kamba. 145 00:07:50,420 --> 00:07:53,950 Kwa mfano, kama mimi kuwa na idadi baadhi ya mbwa na baadhi ya idadi ya paka, 146 00:07:53,950 --> 00:07:59,210 Mimi kuweka placeholders mbili hapa na kisha yangu vigezo mbili ili husika. 147 00:07:59,210 --> 00:08:03,130 >> Hivyo sasa kwamba sisi kujua jinsi ya magazeti maadili kuhifadhiwa katika vigezo, 148 00:08:03,130 --> 00:08:06,030 Jambo la mwisho sana kufanya ni kuhakikisha kwamba sisi 149 00:08:06,030 --> 00:08:10,920 magazeti thamani katika format halisi unahitajika katika vipimo. 150 00:08:10,920 --> 00:08:14,990 Pamoja na kwamba, tumekuwa ilisababisha user na kuthibitishwa mchango wao. 151 00:08:14,990 --> 00:08:17,920 Tumekuwa kisha mahesabu sawa idadi ya chupa za maji 152 00:08:17,920 --> 00:08:22,100 kwamba wao hutumia wakati wa kuoga yao, na tumekuwa outputted kwamba thamani kwao. 153 00:08:22,100 --> 00:08:24,440 Na hivyo, tumekuwa maji kukamilika. 154 00:08:24,440 --> 00:08:28,730 >> Jina langu ni [? Zamila,?] na hii ni CS50. 155 00:08:28,730 --> 00:08:29,909